1).Find the difference between the 30th

and the 34th term of the series 16, 32, 48, 64….

and the 34th term of the series 16, 32, 48, 64….

a)

72

72

b)

66

66

c)

68

68

d)

64

64

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2).The LCM of two numbers is 55 times their

HCF. The sum of the LCM and the HCF is 6272. If one number is 280, then the

other number is

HCF. The sum of the LCM and the HCF is 6272. If one number is 280, then the

other number is

a)

2464

2464

b)

3226

3226

c)

6272

6272

d)

2326

2326

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3).The total earning of A, B and C is Rs 95000

and they save 30%, 25% and 20% of their incomes respectively. If savings are in

the ratio of 4: 5: 6, then what is the difference between the amount of

earnings of B and C?

and they save 30%, 25% and 20% of their incomes respectively. If savings are in

the ratio of 4: 5: 6, then what is the difference between the amount of

earnings of B and C?

a)

Rs. 21000

Rs. 21000

b)

Rs. 9000

Rs. 9000

c)

Rs. 18000

Rs. 18000

d)

Rs. 15000

Rs. 15000

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4).The numbers of boys and girls in a college

are in the ration of 4: 1. If 50% of the boys and 75% of the girls are adults,

the percentage of students who are not adults is?

are in the ration of 4: 1. If 50% of the boys and 75% of the girls are adults,

the percentage of students who are not adults is?

a)

40%

40%

b)

45%

45%

c)

30%

30%

d)

50%

50%

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5).A trader sells his goods at 20% profit. Had

he bought it at 10% more and sold it for Rs. 70 more, he would have gained 25%.

Find the cost price of the goods.

he bought it at 10% more and sold it for Rs. 70 more, he would have gained 25%.

Find the cost price of the goods.

a)

Rs. 800

Rs. 800

b)

Rs. 200

Rs. 200

c)

Rs. 400

Rs. 400

d)

Rs. 600

Rs. 600

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6).The difference between a discount of 40% on

Rs. 1000 and two successive discount of 36% and 5% on the same amount is:

Rs. 1000 and two successive discount of 36% and 5% on the same amount is:

a)

Rs. 8

Rs. 8

b)

Rs. 4

Rs. 4

c)

Rs. 16

Rs. 16

d)

Rs. 24

Rs. 24

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7).At the certain rate of simple interest a

sum becomes double in 14 years. In how many years will it become 4 times itself?

sum becomes double in 14 years. In how many years will it become 4 times itself?

a)

58 years

58 years

b)

42 years

42 years

c)

28 years

28 years

d)

56 years

56 years

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8).A sum of money becomes Rs. 2500 in 2 years

and Rs. 5184 in 4 years on compound interest. Find the rate of compound

interest.

and Rs. 5184 in 4 years on compound interest. Find the rate of compound

interest.

a)

44%

44%

b)

50%

50%

c)

40%

40%

d)

36%

36%

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9).In a military camp, ration was stored for

660 militants at the rate of 800 gramps per militant for 45 days. After 10 days

some more militants came from other camp and the remaining ration got finished

only in 15 days at the rate of 1400 gramps per militant. Find the number of

militants coming in.

660 militants at the rate of 800 gramps per militant for 45 days. After 10 days

some more militants came from other camp and the remaining ration got finished

only in 15 days at the rate of 1400 gramps per militant. Find the number of

militants coming in.

a)

240

240

b)

248

248

c)

240

240

d)

220

220

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10).16 men or 20 boys can do a piece of work

in 30 days. The number of days that 15 men and 15 boys would take to finish the

same work is

in 30 days. The number of days that 15 men and 15 boys would take to finish the

same work is

a)

13×7/9

13×7/9

b)

17×1/7

17×1/7

c)

15×5/9

15×5/9

d)

17×7/9

17×7/9

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__Check here below for the detailed__

solution of the above aptitude questions:

solution of the above aptitude questions

1.)

Given series 16, 32, 48, 64 ….

Given series 16, 32, 48, 64 ….

Common

difference (d) = 32 – 16 = 16

difference (d) = 32 – 16 = 16

First

term = (a) = 16

term = (a) = 16

30th

term = t30 = a + (n – 1) d

term = t30 = a + (n – 1) d

=

16 + (30 – 1) 16

16 + (30 – 1) 16

=

16 + 29 × 16 = 480

16 + 29 × 16 = 480

Now,

34th term = t34= a + (n-1) d

34th term = t34= a + (n-1) d

=

16 + (34 – 1) 16

16 + (34 – 1) 16

=

16 + 33 × 16 = 544

16 + 33 × 16 = 544

Required

difference = 544 – 480 = 64

difference = 544 – 480 = 64

**Answer: d**

2).

Let the HCF be x.

Let the HCF be x.

So,

LCM =55x

LCM =55x

According

to the question,

to the question,

55x

+ x = 6272

+ x = 6272

Or,

56x = 6272

56x = 6272

X

= 112

= 112

Now,

LCM × HCF = First number × Second number

LCM × HCF = First number × Second number

Or,

55x × x = 280 × second number

55x × x = 280 × second number

Or,

55 × 112 × 112 = 280 × second number

55 × 112 × 112 = 280 × second number

Second

number = (55×112×112)/280

number = (55×112×112)/280

=

2464

2464

**Answer: a**

3).

Saving percentages of A, B and C are 30%, 25% and 20% respectively.

Saving percentages of A, B and C are 30%, 25% and 20% respectively.

Now,

(A×30)/100: (B×25)/100: (C×20)/100 = 4: 5: 6

(A×30)/100: (B×25)/100: (C×20)/100 = 4: 5: 6

Or,

3A/10: B/4: C/5 = 4: 5: 6

3A/10: B/4: C/5 = 4: 5: 6

Or,

6A: 5B: 4C = 4/6: 5/5: 6/4

6A: 5B: 4C = 4/6: 5/5: 6/4

A:

B: C = 2/3:1:3/2

B: C = 2/3:1:3/2

Multiplying

each ration by 6,

each ration by 6,

A:

B: C = 4:6:9

B: C = 4:6:9

Now

the sum of the ratios = 4 + 6 + 9 = 19

the sum of the ratios = 4 + 6 + 9 = 19

Earning

of B = (6/19) × 95000 = Rs. 30000

of B = (6/19) × 95000 = Rs. 30000

Earning

of C = (9/19) × 95000 = Rs. 45000

of C = (9/19) × 95000 = Rs. 45000

Required

difference = (45000 – 30000)

difference = (45000 – 30000)

=

Rs. 15000

Rs. 15000

**Answer: d**

4).

Let the total number of boys and girls are 100.

Let the total number of boys and girls are 100.

Now,

number of adult boy and girls students

number of adult boy and girls students

=

[(4/5) × 100 × (1/2) + (1/5) × (3/4) × 100)] = 40 + 15 = 55

[(4/5) × 100 × (1/2) + (1/5) × (3/4) × 100)] = 40 + 15 = 55

Number

of non – adult students

of non – adult students

=

(100 – 55) = 45

(100 – 55) = 45

Required

percentage = 45%

percentage = 45%

**Answer: b**

5).

Let the cost price be Rs. 100

Let the cost price be Rs. 100

SP

at 20% profit = Rs. 120

at 20% profit = Rs. 120

CP

on 10% more = Rs. 110

on 10% more = Rs. 110

SP

on 25% profit = (110 × 125)/100 = Rs. 137.5

on 25% profit = (110 × 125)/100 = Rs. 137.5

Difference

of selling price = (137.5 – 120) = Rs. 17.5

of selling price = (137.5 – 120) = Rs. 17.5

On

Rs. 17.5 more the CP is Rs. 100

Rs. 17.5 more the CP is Rs. 100

On

Rs. 70 more the CP is (100/17.5×70)

Rs. 70 more the CP is (100/17.5×70)

=

(100×10×70)/175 = Rs. 400

(100×10×70)/175 = Rs. 400

**Answer: c**

6).

SP at 40% discount = (1000×60)/100 = Rs. 600

SP at 40% discount = (1000×60)/100 = Rs. 600

SP

at 36% and 5% successive discounts

at 36% and 5% successive discounts

=

1000 × (64/100) × (95/100) = Rs. 608

1000 × (64/100) × (95/100) = Rs. 608

Required

difference = (608 – 600) = Rs. 8

difference = (608 – 600) = Rs. 8

**Answer: a**

7).

Let the principal be Rs. 100

Let the principal be Rs. 100

Time

= 14 years

= 14 years

Amount

= Rs. 200

= Rs. 200

Interest

= (200 – 100) = Rs. 100

= (200 – 100) = Rs. 100

Rate

= [(Interest × 100)/(Principal × time)] = [(100×100)/(100×14)] %

= [(Interest × 100)/(Principal × time)] = [(100×100)/(100×14)] %

=

50/7%

50/7%

Now,

amount = Rs. 400

amount = Rs. 400

Interest

= (400 – 100) = Rs. 300

= (400 – 100) = Rs. 300

Time

= (Interest × 100/Principal × Rate) = (300 × 100/100 × 50) × 7

= (Interest × 100/Principal × Rate) = (300 × 100/100 × 50) × 7

=

42 years

42 years

**Answer: b**

8). If a sum of money on compound interest becomes

Rs. x in t1 years and Rs. y in t2 years, (1 + r/100)t2-t1

= y/x

Rs. x in t1 years and Rs. y in t2 years, (1 + r/100)t2-t1

= y/x

Hence,

y = Rs. 5184

y = Rs. 5184

X

= Rs. 2500

= Rs. 2500

t2

= 4 years

= 4 years

t1

= 2 years

= 2 years

So, (1 + r/100)4-2= 5184/2500

Or,

(1+ r/100)2 = 1296/625

(1+ r/100)2 = 1296/625

Or,

1 + r/100 = 36/25

1 + r/100 = 36/25

Or,

r/100 = (36/25) – 1

r/100 = (36/25) – 1

Or,

r = (11/25) × 100

r = (11/25) × 100

r

= 44%

= 44%

**Answer: a**

9).

Remaining time = (45 – 10)

Remaining time = (45 – 10)

=

35 days

35 days

Present

militants = 660

militants = 660

Let

the number of militants coming in be x

the number of militants coming in be x

Total

militants = (660 + x)

militants = (660 + x)

If

x militants had not come, 660 militants would have eaten the remaining ration

at the rate of 800 grams per militant in 35 days ….. (i)

x militants had not come, 660 militants would have eaten the remaining ration

at the rate of 800 grams per militant in 35 days ….. (i)

Now,

(660 + x) militants are the remaining ration at the rate of 1400 gram/militant

in 15 days.

(660 + x) militants are the remaining ration at the rate of 1400 gram/militant

in 15 days.

Then,

660 × 800 × 35 = (660 + x) × 1400 × 15

660 × 800 × 35 = (660 + x) × 1400 × 15

Or,

(660 + x) = (660×800×35)/(1400×15)

(660 + x) = (660×800×35)/(1400×15)

Or,

660 + x = 880

660 + x = 880

Or,

x = 880 – 660

x = 880 – 660

X

= 220

= 220

**Answer: d**

10).

16 men = 20 boys

16 men = 20 boys

1

man = 20/16 = 5/4 boys

man = 20/16 = 5/4 boys

15

men = 75/4 boys

men = 75/4 boys

Total

number of boys = (75/4) + 15 = (75 + 60)/4

number of boys = (75/4) + 15 = (75 + 60)/4

=

135/4 boys

135/4 boys

20

boys can do a piece of work in 30 days.

boys can do a piece of work in 30 days.

1

boy can do a piece of work in 30 × 20 days.

boy can do a piece of work in 30 × 20 days.

135/4

boys can do a piece of work in (30 × 20 × 4)/135 days = 17 × (7/9) days

boys can do a piece of work in (30 × 20 × 4)/135 days = 17 × (7/9) days

**Answer: d**